Logic Problem, Can you solve it?

[07CivicSi]

I know this is really nerdy, but I felt compelled to post it anyways!
(I know you've probably heard it, though. It's quite old.)

If it's zero degrees fahrenheit today, and it is going to be twice as cold tomorrow,
then what is the temperature, in fahrenheit, going to be tomorrow?

I came up with a solution of my own, but it's only half-feasible!

[SiGTi]

-31.72

[foolio_67]

-32.001

[xtv-sidecar]

He** just froze over.... JK
I am not good at this stuff what is it?
My guess would be 0 degrees still.

[ThatOneGuy]

-32 degrees

[Sli(ks]

Convert to celcius, multiply by two, convert back to Fahrenheit, done. lol

-32

[somedaySI]

1/2 way between absolute zero and 0f?

[Driving91LX]

The coldest that you can go is absolute zero, or -459 F.
So, if it were -229.5 F (half of -459) and someone said it was going to be twice as warm you would say -229.5 F + 229.5 F = 0 F.
So I say that twice as cold as 0 F is -229.5 F.
That's my final answer.

[fa1]

229.5 degrees kelvin. Stolen from above lol, I just want to look smart

[07CivicSi]

The statement "twice as cold" makes the problem impossible to solve. "Cold" is simply an absence of heat in varying degrees (from 0 degrees Kelvin to infinity degrees Kelving), meaning that "twice as cold" is a value relative to "warm" or "hot". No reference to "warm" or "hot" was given, thus the problem is mathematically impossible to solve.

Trying to divide 0 degrees or a conversion of 0 to another scale is also inaccurate, as "dividing by two" or "halfing" was not called for: converting to Kelvin and dividing the result by two is not a true solution, as to divide "cold" by two, you must first define it relative to "warm", and as discussed in the previous paragraph, that is impossible


you are all wrong

[tcel127]

Originally Posted by 07CivicSi

The statement "twice as cold" makes the problem impossible to solve. "Cold" is simply an absence of heat in varying degrees (from 0 degrees Kelvin to infinity degrees Kelving), meaning that "twice as cold" is a value relative to "warm" or "hot". No reference to "warm" or "hot" was given, thus the problem is mathematically impossible to solve.

Trying to divide 0 degrees or a conversion of 0 to another scale is also inaccurate, as "dividing by two" or "halfing" was not called for: converting to Kelvin and dividing the result by two is not a true solution, as to divide "cold" by two, you must first define it relative to "warm", and as discussed in the previous paragraph, that is impossible


you are all wrong

Damn... wheres my Advil.

[Torredo]

no shit!

i need a few advil please...lmao

[Driving91LX]

Originally Posted by 07CivicSi

The statement "twice as cold" makes the problem impossible to solve. "Cold" is simply an absence of heat in varying degrees (from 0 degrees Kelvin to infinity degrees Kelving), meaning that "twice as cold" is a value relative to "warm" or "hot". No reference to "warm" or "hot" was given, thus the problem is mathematically impossible to solve.

Trying to divide 0 degrees or a conversion of 0 to another scale is also inaccurate, as "dividing by two" or "halfing" was not called for: converting to Kelvin and dividing the result by two is not a true solution, as to divide "cold" by two, you must first define it relative to "warm", and as discussed in the previous paragraph, that is impossible


you are all wrong

From what I can remember, you can't get any colder than 0 Kelvin or hotter than 100 Kelvin (on Earth). That's why I used absolute zero as the starting point. I still think that based on that scale, -229.5 F is twice as cold as 0 F.
But what do I know...
"Damn it Jim! I'm a software engineer, not a physicist!"

[Halcyon819]

Originally Posted by 07CivicSi

The statement "twice as cold" makes the problem impossible to solve. "Cold" is simply an absence of heat in varying degrees (from 0 degrees Kelvin to infinity degrees Kelving), meaning that "twice as cold" is a value relative to "warm" or "hot". No reference to "warm" or "hot" was given, thus the problem is mathematically impossible to solve.

Trying to divide 0 degrees or a conversion of 0 to another scale is also inaccurate, as "dividing by two" or "halfing" was not called for: converting to Kelvin and dividing the result by two is not a true solution, as to divide "cold" by two, you must first define it relative to "warm", and as discussed in the previous paragraph, that is impossible


you are all wrong

I concur. Cold has not been defined mathematically in this problem.

[UncleSid]

its going to be really freakin cold tomorrow. 0 is just freakin cold.

[somedaySI]

Originally Posted by 07CivicSi

The statement "twice as cold" makes the problem impossible to solve. "Cold" is simply an absence of heat in varying degrees (from 0 degrees Kelvin to infinity degrees Kelving), meaning that "twice as cold" is a value relative to "warm" or "hot". No reference to "warm" or "hot" was given, thus the problem is mathematically impossible to solve.

Trying to divide 0 degrees or a conversion of 0 to another scale is also inaccurate, as "dividing by two" or "halfing" was not called for: converting to Kelvin and dividing the result by two is not a true solution, as to divide "cold" by two, you must first define it relative to "warm", and as discussed in the previous paragraph, that is impossible


you are all wrong

you implied that it is 0f "warm" or "hot" by giving that temperature

[ExCoupe06]

know what..? im not gonna worry bout it no more, coz i know it will be warmer here in texas..lol...

next question please..?

:-)

[Pukuyo]

Originally Posted by Sli(k

Convert to celcius, multiply by two, convert back to Fahrenheit, done. lol

-32

^^^ this is the right logic. i did not do the calculations so i'm not sure about the number Slik provided. but if you follow this, then you should get the right answer. makes sense to me.

[BATANG CITY JAIL]

00 is my answer.

[imtim25]

the answer is: who gives a S***, its F***** FREEZING!